Asked by kitor
                Note: You can get full credit for this problem by just answering the last question correctly. The initial questions are meant as hints towards the final answer and also allow you the opportunity to get partial credit.
Consider the definite integral from pi/6 to pi/2 cos(z)/sin5(z)dz
Then the most appropriate substitution to simplify this integral is
u =
Then dz=f(z)du where
f(z) =
After making the substitution and simplifying we obtain the integral abg(u)du where
g(u) =
a =
b =
This definite integral has value =
Help please!!!! can't understand !!
            
            
        Consider the definite integral from pi/6 to pi/2 cos(z)/sin5(z)dz
Then the most appropriate substitution to simplify this integral is
u =
Then dz=f(z)du where
f(z) =
After making the substitution and simplifying we obtain the integral abg(u)du where
g(u) =
a =
b =
This definite integral has value =
Help please!!!! can't understand !!
Answers
                    Answered by
            Steve
            
    I assume you mean
∫cos(z)/sin^5(z) dz
If u = sin(z), then du = cos(z) dz and we have
∫u^-5 du
= -1/4 u^-4
Now the limits of integration become [1/2,1] because u = sin(z)
Now it's easy to evaluate:
(-1/4 * 1^-4)-(-1/4 * 2^4) = 15/4
    
∫cos(z)/sin^5(z) dz
If u = sin(z), then du = cos(z) dz and we have
∫u^-5 du
= -1/4 u^-4
Now the limits of integration become [1/2,1] because u = sin(z)
Now it's easy to evaluate:
(-1/4 * 1^-4)-(-1/4 * 2^4) = 15/4
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