Asked by Breauna
The gas phase decomposition of dinitrogen pentoxide at 335 K
N2O5(g) 2 NO2(g) + ½ O2(g)
is first order in N2O5.
During one experiment it was found that when the initial concentration of N2O5 was 0.218 M, the concentration of N2O5 dropped to 2.96E-2 M after 282 s had passed.
Based on this experiment, the rate constant for the reaction is
N2O5(g) 2 NO2(g) + ½ O2(g)
is first order in N2O5.
During one experiment it was found that when the initial concentration of N2O5 was 0.218 M, the concentration of N2O5 dropped to 2.96E-2 M after 282 s had passed.
Based on this experiment, the rate constant for the reaction is
Answers
Answered by
DrBob222
rate = -delta [N2O5]/delta time
rate = (0.218-0.0296)/282 = ?
Then rate = k[A]. Calculate k.
rate = (0.218-0.0296)/282 = ?
Then rate = k[A]. Calculate k.
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