Asked by jenny
                csc^4-cot^4= 1+cos^2/sin^2
i need help! please help me
            
        i need help! please help me
Answers
                    Answered by
            Reiny
            
    LS = (csc^2 Ø + cot^2 Ø)(csc^2 Ø - cot^2 Ø
= (1 + cot^2 Ø + cot^2 Ø)(1+cot^2 Ø - cot^2 Ø
= 1 + 2cot^2 Ø
RS = (1 + cos^2 Ø)/sin^2 Ø
= (sin^2 Ø + cos^2 Ø + cos^2 Ø)/sin^2 Ø
= (sin^2 Ø + 2cos^2 Ø)/sin^2 Ø
= 1 + 2 cot^2 Ø
= LS
    
= (1 + cot^2 Ø + cot^2 Ø)(1+cot^2 Ø - cot^2 Ø
= 1 + 2cot^2 Ø
RS = (1 + cos^2 Ø)/sin^2 Ø
= (sin^2 Ø + cos^2 Ø + cos^2 Ø)/sin^2 Ø
= (sin^2 Ø + 2cos^2 Ø)/sin^2 Ø
= 1 + 2 cot^2 Ø
= LS
                    Answered by
            Reiny
            
    forgot to mention that you cannot just skip the "angle" after a trig operator.
What you typed would be like having an equation of the type ...
√ = ∫ + ∑
    
What you typed would be like having an equation of the type ...
√ = ∫ + ∑
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