Asked by Kiki
Use a graphical method to find a solution to the following system of equations in the interval –1 ≤ x ≤ 5:
y = x2 – 4x + 2
y = x + 2
The solution set to this system of equations in the interval –1 ≤ x ≤ 5 is
{}
{(2, 0)}
{(0, 2), (5, 7)}
{(2, 0), (7, 5)}
y = x2 – 4x + 2
y = x + 2
The solution set to this system of equations in the interval –1 ≤ x ≤ 5 is
{}
{(2, 0)}
{(0, 2), (5, 7)}
{(2, 0), (7, 5)}
Answers
Answered by
Reiny
Why are you calling this trig ?
x^2 - 4x + 2 = x+2
x^2 - 5x = 0
x(x-5) = 0
x = 0 or x = 5
sub in those x's in either of the two equations to find the y, then choose your answer.
http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E2+–+4x+%2B+2%2C++y+%3D+x+%2B+2
x^2 - 4x + 2 = x+2
x^2 - 5x = 0
x(x-5) = 0
x = 0 or x = 5
sub in those x's in either of the two equations to find the y, then choose your answer.
http://www.wolframalpha.com/input/?i=plot+y+%3D+x%5E2+–+4x+%2B+2%2C++y+%3D+x+%2B+2
Answered by
Kiki
I got choice 3 is that correct
Answered by
Reiny
of course
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