Asked by Andy G
The concentration C of a chemical in the bloodstream t hours after injection into muscle tissue is C=(3t+t)/(t^3+50)
a. determine the horizontal asymptote of the function and interpret its meaning in the context of the problem.
b. use a graphing utility to graph the function and approximate the time when the bloodstream concentration is greatest.
a. determine the horizontal asymptote of the function and interpret its meaning in the context of the problem.
b. use a graphing utility to graph the function and approximate the time when the bloodstream concentration is greatest.
Answers
Answered by
bobpursley
divide numerator and denominator by t^3
C=(3/t^2 + 1/t^2)/(1+50/t^3)
as t>>>very large, then
C=(0/1)=0 which means the chem is gone.
C=(3/t^2 + 1/t^2)/(1+50/t^3)
as t>>>very large, then
C=(0/1)=0 which means the chem is gone.
Answered by
Ben Dover III
A. C=0
This indicates that the concentration of the chemical into the muscle tissue eventually dissipates.
B. t= 4.5 hours
C. C < 0.355 when 0 ≤ t ≤ 2.72 hours and t > 8.03 hours.
These are the right answers trust me or don't, doesn't matter to me if you get the answers wrong.
P.S - That isn't really my name
Gotta Blast
This indicates that the concentration of the chemical into the muscle tissue eventually dissipates.
B. t= 4.5 hours
C. C < 0.355 when 0 ≤ t ≤ 2.72 hours and t > 8.03 hours.
These are the right answers trust me or don't, doesn't matter to me if you get the answers wrong.
P.S - That isn't really my name
Gotta Blast
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