The rate constant,K, for a given was determined at a number of temperatures. A graph of log K versus the reciprocal of the kelvin temperature yielded a straight line with a slope of -250 K. What is the activation energy of this reaction in Kj/mol?

Question

For this question I got 2.08kj/mol

Answer 1

I don't have my calculator handy but that looks right to me.
250 * about 8 = about 2000 J/mol