Question
an aluminium of mass 2.1 kg rests on a steel platform. A horizontal force of 15N is applied to block(a) given the coefficient of limiting friction is 0.61 will the block move? (b)if it moves what will be its acceleration?
Answers
Damon
2.1 * 9.81 * .61 = 12.57 Newtons maximum friction force
so no
15 - 12.56 = 2.43 Newton net force
a = F/m = 2.43 / 2.1 = 1.16 m/s^2
so no
15 - 12.56 = 2.43 Newton net force
a = F/m = 2.43 / 2.1 = 1.16 m/s^2
Esther
I need the question please
Esther
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