Asked by Bebang Biskobengboom
Mike’s father is twice as old as he is. Seven years ago, the father was 7 years less than thrice as old as Mike was. Find Mike’s present age.
Answers
Answered by
Reiny
List their ages at the two different times
NOW:
Mike's age --- x
father's age -- 2x
7 YEARS AGO:
Mike ---- x-7
father ---- 2x-7
It said: " (7 yrs ago) the father was 7 years less than thrice as old as Mike was
---> 2x-7 = 3(x-7) - 7
2x - 7 = 3x - 21 - 7
-x = -21
x = 21
Mike is now 21 , his father now is 42
check:
7 years ago, Mile was 14, his father was35
Is 35 equal to 3 times 14 less 7 ?? YES
NOW:
Mike's age --- x
father's age -- 2x
7 YEARS AGO:
Mike ---- x-7
father ---- 2x-7
It said: " (7 yrs ago) the father was 7 years less than thrice as old as Mike was
---> 2x-7 = 3(x-7) - 7
2x - 7 = 3x - 21 - 7
-x = -21
x = 21
Mike is now 21 , his father now is 42
check:
7 years ago, Mile was 14, his father was35
Is 35 equal to 3 times 14 less 7 ?? YES
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