Asked by Jay
                 A family has two cars. The first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of 30 miles per gallon of gas. During one particular week, the two cars went a combined total of 1250 miles, for a total gas consumption of 35 gallons. How many gallons were consumed by each of the two cars that week? 
            
            
        Answers
                    Answered by
            Reiny
            
    let distance covered by the 40 mpg car be x miles
let the distance covered by the 30 mpg car be 1250-x
miles
gas used by the 40 mpg car = x/40
gas used by the 30 mpg car = (1250-x)/30
x/40 + (1250-x)/30 = 35
times 120
3x + 4(1250-x) = 4200
-x = -800
x = 800
So the more efficient car went 800 miles and used 20 gallons
the other car went 1250-800 or 450 miles and used 15 gallons
    
let the distance covered by the 30 mpg car be 1250-x
miles
gas used by the 40 mpg car = x/40
gas used by the 30 mpg car = (1250-x)/30
x/40 + (1250-x)/30 = 35
times 120
3x + 4(1250-x) = 4200
-x = -800
x = 800
So the more efficient car went 800 miles and used 20 gallons
the other car went 1250-800 or 450 miles and used 15 gallons
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