since PE=mgh and KE = 1/2 mv^2,
gh = 1/2 v^2
(9.8)(2) = 1/2 v^2
. . .
in a game a toy car slides down a slop if the top of the slope is 2 m higher than the foot of the slope how fast will the car be moving when it reaches the foot assume that all of its g.p.e is transformed to k.e (i'm 8th grade so simple answers pleas)
3 answers
thx man
I really needed help from that. I thought there wasn't enough information but thanks a lot!