A gas cylinder of volume 26 liters contains an ideal gas at temperature 27 degrees C and pressure 1920 kPa. Some of the gas leaks until the pressure falls to 1500 kPa. How many moles of gas leaked, assuming that the temperature remains constant during this process?

Answer 1

P V = n R T

Final state:
P = 1.5*10^6 N/m^2
V = 26 liters = 26*10^-3 m^3
T =273+27 = 300 K
so
n R = PV/T = 1.5*26*10^3/300
= .13 * 10^3
R =8.314
so
n = .13*10^3/8.314 = 15.6 moles

Do that again for 1.92*10^6 N/m^2
and get a bigger initial n

then subtract

Answer 2

I got 1, is that right?

Answer 3

You mean I have to do it?

Answer 4

I can figure it out. Thanks for your help

Answer 5

1.92 /1.5 = 1.28

1.28* 15.6 = 19.97

19.97 - 15.6 = 4.37