Asked by Riley
A gas cylinder of volume 26 liters contains an ideal gas at temperature 27 degrees C and pressure 1920 kPa. Some of the gas leaks until the pressure falls to 1500 kPa. How many moles of gas leaked, assuming that the temperature remains constant during this process?
Answers
Answered by
Damon
P V = n R T
Final state:
P = 1.5*10^6 N/m^2
V = 26 liters = 26*10^-3 m^3
T =273+27 = 300 K
so
n R = PV/T = 1.5*26*10^3/300
= .13 * 10^3
R =8.314
so
n = .13*10^3/8.314 = 15.6 moles
Do that again for 1.92*10^6 N/m^2
and get a bigger initial n
then subtract
Final state:
P = 1.5*10^6 N/m^2
V = 26 liters = 26*10^-3 m^3
T =273+27 = 300 K
so
n R = PV/T = 1.5*26*10^3/300
= .13 * 10^3
R =8.314
so
n = .13*10^3/8.314 = 15.6 moles
Do that again for 1.92*10^6 N/m^2
and get a bigger initial n
then subtract
Answered by
Randall
I got 1, is that right?
Answered by
Damon
You mean I have to do it?
Answered by
Riley
I can figure it out. Thanks for your help
Answered by
Damon
1.92 /1.5 = 1.28
1.28* 15.6 = 19.97
19.97 - 15.6 = 4.37
1.28* 15.6 = 19.97
19.97 - 15.6 = 4.37
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