Asked by Riley
A can of gasoline has a rectangular base with dimensions of 13.5 cm by 13 cm. If there are 3 liters of gasoline in the can, how much does the surface of the gasoline rise (in mm) in the can when the temperature is raised by 45C? The coefficient for volume expansion of gasoline is 9.5 10-4/C.
Answers
Answered by
Damon
change in volume = surface area * delta h
delta volume/volume = 45 * 9.5 * 10^-4
volume = 3 liters = 3*10^-3 m*3
so
delta volume = 3 *10^-7 *45 * 9.5
= 1282*10^-7 m^3
surface area = .135*.13 = 1.755*10^-2
so
1.282*10^-4 = 1.755 *10^-2 delta h
delta h = .73 * 10^-2 meters
or .73 cm
delta volume/volume = 45 * 9.5 * 10^-4
volume = 3 liters = 3*10^-3 m*3
so
delta volume = 3 *10^-7 *45 * 9.5
= 1282*10^-7 m^3
surface area = .135*.13 = 1.755*10^-2
so
1.282*10^-4 = 1.755 *10^-2 delta h
delta h = .73 * 10^-2 meters
or .73 cm
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.