I'd use elimination, since the coefficients are small
to eliminate x, subtract the 1st two, subtract twice #1 from #3 and we have
-5y - z = -18
-9y + 5z = -26
now eliminate y or z in the same way, and then plug the values back in to obtain the others.
Explain, in complete sentences, which method you would use to solve the following system of equations and why you chose that method. Provide the solution to the system.
x - 3y + 2z = -12
x + 2y + 3z = 6
2x - 3y - z = -2
2 answers
What strategy did you use to solve 5? Explain the step in complete sentences