Asked by Anonymous
ALLY HAD A GAME WITH 2 GROUPS OF PLAYING TILES. THE FIRST GROUP OF 24 TILES HAD ALL THE LETTERS OF THE ALPHABET EXCEPT U AND Y. EACH TILE HAD 1 LETTER ON IT. THE SECOND GROUP OF 5 TILES HAD THE NUMBERS 1 THROUGH 5, WITH 1 NUMBER ON EACH TILE. IF ALLY DREW 1 LETTER TILE AND 1 NUMBER TILE AT RANDOM. WHAT IS THE PROBABILITY THAT SHE WOULD DRAW A LETTER IN HER NAME AND AN EVEN NUMBER?
Answers
Answered by
Reiny
Why is your caps lock stuck on your keyboard ?
Two of her letters in her name are found in the 24 letter group, and there are 2 evens in the group of number tiles
prob(a letter in her name and an even)
= (2/25)(2/5)
= 4/125
Two of her letters in her name are found in the 24 letter group, and there are 2 evens in the group of number tiles
prob(a letter in her name and an even)
= (2/25)(2/5)
= 4/125
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