The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method.

Answer 1

5n+2m=18
3n-7m=-22

can you solve this?

Answer 2

translate the English into Math
"The sum of five times a number and twice a second number is 18" ---->5x + 2y = 18
"the difference of three times the first number and seven times the second number is -22" ---> 3x - 7y = -22

1st times 7 -- 35x + 14y = 126
2nd times 2 -- 6x - 14y = -44
add them
41x = 82
x = 82/41= 2

into the 1st

5(2) + 2y = 18
10 + 2y = 18
2y = 8
y = 4

Answer 3

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