Asked by Stefan
So I have the balanced equation:
c3H8 +502 = 3C02 +4H20
Question: At STP propane (C3H8) burns in oxygen to form 2.15L of carbon dioxide and water.
So I've got 2.15 L x 1 mole /22.4 L
But when I try to do the mole ratio, I don't know what to do since the 2.15 L is of carbon dioxide and water.
c3H8 +502 = 3C02 +4H20
Question: At STP propane (C3H8) burns in oxygen to form 2.15L of carbon dioxide and water.
So I've got 2.15 L x 1 mole /22.4 L
But when I try to do the mole ratio, I don't know what to do since the 2.15 L is of carbon dioxide and water.
Answers
Answered by
DrBob222
See you post above.
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