Asked by Courtney

What mass of AgN03 would you dissolve in water to get 1g of silver?

11 years ago

Answered by Damon

AgNO2 = 108 + 14 +3(16) = 170 g/mol
Ag = 108 g/mol

so AgNO3 is 108 grams silver/170 grams Agno3

1 gram silver(170 g AgNO3/108 g Ag)
= 1.57 grams

11 years ago

Answered by Courtney

thanks!

11 years ago

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