Asked by josh
a.Find the slope of the tangent line to the curve y=9-2x^2 at the point (2,1)
b.Find an equation of this tangent line.
b.Find an equation of this tangent line.
Answers
Answered by
Steve
as you know, the slope of the tangent line is just the derivative. So,
y'(x) = -4x
giving us
y'(2) = -8
and now we have a point and a slope, so the line is
y-1 = -8(x-2)
y'(x) = -4x
giving us
y'(2) = -8
and now we have a point and a slope, so the line is
y-1 = -8(x-2)
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