Asked by Sam
A bus slows down uniformly from 75 km/h to 15 km/h in 12.55 s. How far did the car travel before stopping?
Answers
Answered by
Henry
a=(V-Vo)/t = (15-75)/12.55 = -4.78 m/s^2
d = Vo*t + 0.5*a*t^2
d = 75*12.55 + 0.5*(-4.78)*12.55^2 =
564.8 m.
d = Vo*t + 0.5*a*t^2
d = 75*12.55 + 0.5*(-4.78)*12.55^2 =
564.8 m.
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