To solve this problem, let's start by finding the distance covered by the ant when walking around the triangle twice.
An equilateral triangle has equal sides, so each side has a length of 10 m. Since the ant walks completely around the triangle twice, it covers a total distance of 10 m x 3 = 30 m.
Next, let's find the distance covered by the beetle when walking around the square.
A square has equal sides, so each side has a length of 15 m. The beetle walks around the square two and a half times faster than the ant. This means that the beetle covers a total distance of 15 m x 4 x 2.5 = 150 m.
Now, to determine how many laps of the square the beetle would have made in the same time, we can divide the total distance covered by the beetle (150 m) by the distance covered in one lap of the square (15 m).
150 m รท 15 m = 10 laps
Therefore, the beetle would have made 10 laps of the square in the same time it took the ant to walk around the triangle twice.