Asked by Helen
An initial population of 298 quail increases at an annual rate of 8%. Write an exponential function to model the quail population. What will the approximate population be after 3 years
f(x)=298(1.08)^x;375
f(x)=298(0.08)^x;153
f(x)=298(8)^x;305
f(x)=(298*1.08)^x;324
f(x)=298(1.08)^x;375
f(x)=298(0.08)^x;153
f(x)=298(8)^x;305
f(x)=(298*1.08)^x;324
Answers
Answered by
Reiny
number = 298(1.08)^n , where n is the number of years
so when n = 3
population = 298(1.08)^3 = appr 375
so when n = 3
population = 298(1.08)^3 = appr 375
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