Asked by Caleb
Write the equation of the line in standard form:
(-3, 6); m = 1/2
(1, 0) & (-5, 3)
(-5, -5) & (-1, 3)
(-3, 6); m = 1/2
(1, 0) & (-5, 3)
(-5, -5) & (-1, 3)
Answers
Answered by
bobpursley
I will do one:
(-3, 6); m = 1/2
y=mx+b
6=1/2 * (-3) + b
solve for b.
now standard form:
http://www.mathwarehouse.com/algebra/linear_equation/standard-form-equation-of-a-line.php
Ax+By=C
y=mx+b
you know m, b
y=1/2 x + b
2y=x+2b
x-2y=-2b put in b, and you have it.
(-3, 6); m = 1/2
y=mx+b
6=1/2 * (-3) + b
solve for b.
now standard form:
http://www.mathwarehouse.com/algebra/linear_equation/standard-form-equation-of-a-line.php
Ax+By=C
y=mx+b
you know m, b
y=1/2 x + b
2y=x+2b
x-2y=-2b put in b, and you have it.
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