Asked by Priya
Find sin (alpha/2) and cos (alpha/2)
sin alpha = 3, -pi/2 < alpha <less then or equal to 0
How to get the answer of sin (alpha/2) = -1/square root 3, cos(alpha/2) = square root 6/3?
sin alpha = 3, -pi/2 < alpha <less then or equal to 0
How to get the answer of sin (alpha/2) = -1/square root 3, cos(alpha/2) = square root 6/3?
Answers
Answered by
Reiny
You said "sin alpha = 3"
check your typing, the sine of any angle must be between ±1
Looking at your answers, α/2 is in the fourth quadrant, with x=√2, y=-1, and r=√3
check your typing, the sine of any angle must be between ±1
Looking at your answers, α/2 is in the fourth quadrant, with x=√2, y=-1, and r=√3
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