100% please im gonna fail.

Question

2. Use the image to answer the question (0,1) and (1,-4).
Write the equation in the slope-intercept form.
3. Graph the linear equation y = -3x + 2.
4. Use the image to answer the question. (0,3) and (3,2)
Is this the correct graph of y = -1/3 x + 4?
A. Yes, it is the correct graph because this graph has a y-intercept of (0,4).
B. No, it is not the correct graph because this graph has a y-intercept of (0,3).
C. Yes it is the correct graph because this graph has a y-intercept of (0,3).
D. No, it is not the correct graph because this graph has a positive slope.
5. Graph the linear equation. y = 2/3 x - 1.

Answer 1

To answer question 2, we can use the given points (0,1) and (1,-4) to find the slope-intercept form of the linear equation.

First, let's find the slope (m) using the slope formula:
m = (y2 - y1)/(x2 - x1)
m = (-4 - 1)/(1 - 0)
m = -5/1
m = -5

Now that we have the slope, we can use one of the given points (0,1) and the slope to find the y-intercept (b) using the slope-intercept form of an equation (y = mx + b):
1 = -5(0) + b
1 = b

Now we can write the equation in slope-intercept form:
y = -5x + 1

For question 3, we need to graph the linear equation y = -3x + 2. To do this, we can plot the y-intercept (0,2) and then use the slope of -3 to find additional points to plot. There are multiple ways to do this, but one method is as follows:

Plot the y-intercept (0, 2).
Using the slope of -3, move down 3 units and then move right 1 unit to find another point.
Connect the two points to graph the line.

For question 4, we need to determine if the given graph is correct for the equation y = -1/3x + 4. To do this, we can compare the graph to the equation.

The equation y = -1/3x + 4 has a y-intercept of (0,4), not (0,3), so the correct answer is:
D. No, it is not the correct graph because this graph has a positive slope.

For question 5, we need to graph the linear equation y = 2/3x - 1. To do this, we can plot the y-intercept (0, -1) and then use the slope of 2/3 to find additional points to plot. There are multiple ways to do this, but one method is as follows:

Plot the y-intercept (0, -1).
Using the slope of 2/3, move up 2 units and then move right 3 units to find another point.
Connect the two points to graph the line.