by definition √-1 = i
so rewrite
(10√-13)(-5√-5) as
(10√-1√13)(-5√-i√5)
= (10i√13)(-5i√5)
= -50i^2√65
= +50√5
(10 Squar root -13)(-5 square root -5)
put in standard form a+bi
I really don't understand square roots so can you show me how to do these please
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