10 mL of 0.1 HCl was added to 9mL of water. 10 mL of that solution was added to another 90 mL of water. The student diluted the sample as above 1 time(s). What is the pH of the solution?

Answer 1

first dilution: you diluted it to 10/19 of .1M, so it is 10/190 M.
Then you diluted it 10/100 of its concentration, new concentration 10/1900 M

the statement <The student diluted the sample as above 1 time(s).>> makes no sense to me, it it means my first paragraph, then the concentration is 10/1900 M

pH=-log(10/1900)=2.28

check all that.