10. Exponential Functions in Context(1 point)

Complete the table below.

Recall that the equations for Exponential Growth is f(x) = a(1+r)t
and the Exponential Rate of Decay is f(x) = a(1−r)t

Part A: Determine if the situation is a rate of decay or growth. Write "decay" or "growth"

Part B: Determine the rate of decay or growth (r-value).

Part C: Determine the function of the scenario. Do not include commas in your equation. Simplify your function.

Scenario Decay or Growth? r-value Function

South Carolina has found that the manatee population is increasing.

In 2024, there were 1,014 manatees with a rate of increase of 3.1% per year.

growth 0.031 f(x) =
1014(1.031)t

A typical cup of tea contains about 25 milligrams (mg) of caffeine.

Every hour, approximately 3% of the amount of caffeine in the body is

metabolized and eliminated.

f(x) =

In 2024, the population of the local high school is

314 students with an annual rate of increase of 1.18%.

f(x) =

The value of a 2024 Toyota Prius was $44,205 when it went on the

market. It depreciates at a rate of 10.5% per year

f(x) =

1 answer

Let's break down each of the scenarios according to the instructions provided.

Scenario 1: Manatee Population

  • Part A: Since the manatee population is increasing, this is a growth situation.
  • Part B: The rate of growth is provided as 3.1%, or in decimal form, 0.031.
  • Part C: The function can be written as: \[ f(x) = 1014(1 + 0.031)^{t} = 1014(1.031)^{t} \]

Scenario 2: Caffeine Metabolism

  • Part A: Since the amount of caffeine is decreasing due to metabolism, this is a decay situation.
  • Part B: The rate of decay is 3%, or in decimal form, 0.03.
  • Part C: The function can be written as: \[ f(x) = 25(1 - 0.03)^{t} = 25(0.97)^{t} \]

Scenario 3: High School Population

  • Part A: Since the population of the high school is increasing, this is a growth situation.
  • Part B: The rate of growth is 1.18%, or in decimal form, 0.0118.
  • Part C: The function can be written as: \[ f(x) = 314(1 + 0.0118)^{t} = 314(1.0118)^{t} \]

Scenario 4: Depreciation of Toyota Prius

  • Part A: Since the value of the car is decreasing, this is a decay situation.
  • Part B: The rate of decay is 10.5%, or in decimal form, 0.105.
  • Part C: The function can be written as: \[ f(x) = 44205(1 - 0.105)^{t} = 44205(0.895)^{t} \]

Summary Table:

| Scenario | Decay or Growth? | r-value | Function | |-------------------------------------------------------------------------------------------------------|-------------------|---------|---------------------------| | South Carolina has found that the manatee population is increasing. | growth | 0.031 | \( f(x) = 1014(1.031)^{t} \) | | A typical cup of tea contains about 25 milligrams (mg) of caffeine. Every hour, approximately 3% of the amount of caffeine in the body is metabolized and eliminated. | decay | 0.03 | \( f(x) = 25(0.97)^{t} \) | | In 2024, the population of the local high school is 314 students with an annual rate of increase of 1.18%. | growth | 0.0118 | \( f(x) = 314(1.0118)^{t} \) | | The value of a 2024 Toyota Prius was $44,205 when it went on the market. It depreciates at a rate of 10.5% per year. | decay | 0.105 | \( f(x) = 44205(0.895)^{t} \) |