Asked by Ashlyn
10.6gram of hydrated zinc tetraoxosulphate (vi) on heating to constant mass gave 5.95g of the anhydrous form.Calculate the number of molecules(x) of water of crystalization in the hydrated salt.(zn=65,s=32,o=16,h=1)
Answers
Answered by
DrBob222
10.6-5.95 = g H2O = 4.65
mols H2O = 4.65/18 = ?
mols ZnSO4 = 5.95/molar mass ZnSO4.
Find the ratio of water to 1 mol ZnSO4. The easy way to do that is to divide the mols H2O by mols ZnSO4 and round to a whole number. If I punched in the right numbers on my calculator that shouldb e ZnSO4.7H2O
mols H2O = 4.65/18 = ?
mols ZnSO4 = 5.95/molar mass ZnSO4.
Find the ratio of water to 1 mol ZnSO4. The easy way to do that is to divide the mols H2O by mols ZnSO4 and round to a whole number. If I punched in the right numbers on my calculator that shouldb e ZnSO4.7H2O
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