one of the log properties is .
a^(loga k )
= k
we have that case, if we change
10^(-10log3)
to
10^(log 3^-10)
we get 3^-10 = 1/59049 ---> exact answer
or .000016935
( if I use my calculator
10^(-4.771212547)
= .000016935
10^(-10log3)
How to solve this???
3 answers
do u know how I could find this in a way that creates a fractional form?
As Reiny noted,
3^-10 = 1/59049
3^-10 = 1/59049