10.0 grams of barium chloride (208.3g/mol) is reacted with excess potassium phosphate and 7.22 of grams of barium phosphate (601.8 g/mol) is isolated. calculate the theoretical yield of barium phosphate

1 answer

I suspect a balanced equation is the place to start...

3BaCl2 + 2K3PO4 >>> Ba3(PO4)2 + 6KCl

moles barium phosphate: 1/3 *moles barium chloride

calcuate the moles barium chloride, divide by three, then that is the moles of barium phosphate, convert that to grams of barium phosphate.