1a. Fk = u*Fn = u * Mg = 0.44 * 5.1*9.8 = 22 N. The force of kinetic friction is greater than the applied force. please check for errors.
3a. (4.1/9.8) * 810 = 339 N.
1. You apply a force of 11.8 N on a 5.1 kg object, pushing it horizontally across a surface where the coefficient of kinetic friction is 0.44.
(a) Determine the frictional force acting.
(b) Determine the object's acceleration.
2. A container of mass 0.5 kg slides along the ice with a speed of 6 m/s when it reaches a rough section where the coefficient of kinetic friction is 1. How long will it take the puck to stop sliding?
3. The gravitational field strength on the surface of Mars is 4.1 N/kg.
a) What would a person weigh on Mars if this person weighs 810 N on Earth?
(b) What is the mass of Mars if its radius is 3.4 x 10^8 m?
Help to any of these question would be appreciated.
Thanks,
Shawn
1 answer