1. y = 5x - 4
2. y - 4x + 1 = 0
To show that this system has no solution, we can start by setting the two equations equal to each other:
5x - 4 = 4x - 1
Subtract 4x from both sides:
x - 4 = -1
Add 4 to both sides:
x = 3
Now, we can substitute x back into one of the original equations to solve for y:
y = 5(3) - 4
y = 15 - 4
y = 11
So the solution to the system is x = 3, y = 11. Since there is a unique solution, the system does have a solution and not no solution.
1. y=5x–4: y=5x–4
2. y=–2x+3: y=–2x+3
3. y=3x+1: y=3x+1
4. 2y=6x+2: y=3x+1
5. y–5x=+2: y = 5x + 2
6. y–4x+1=0: y=4x-1
What two equations from those above would form a system with no solution?
You can list the 2 equations here
show work
1 answer