#2 and #3 are trick questions, since |x| >= 0 for all x
|x^2-3x+3|=3
x^2-3x+3=3 or -(x^2-3x+3)=3
In the first case,
x^2-3x+3=3
x^2-2x = 0
x(x-2) = 0
x = 0 or 2
In the second case,
-(x^2-3x+3)=3
x^2-3x+3 = -3
x^2 - 3x + 6 = 0
no real x satisfies the equation
final answer: x = 0 or 2
1. |x^2-3x+3|=3
2. |x^2+2x+1|=-4
3. |3x+2|+3=0
1 answer