1)
Sodium oxide: 2Na + 1/2O2 -> Na2O
Zinc oxide: 2Zn + O2 -> 2ZnO
2) i)
a) 2Na + 2H2O -> 2NaOH + H2
b) 2Al + 6H2O -> 2Al(OH)3 + 3H2
c) Zn + 2H2O -> Zn(OH)2 + H2
d) Fe + 2H2O -> Fe(OH)2 + H2
e) Cu + 2H2O -> No reaction
ii) Reactivity series:
Na > Al > Zn > Fe > Cu
3) Copper remains unreactive with water because it is less reactive than water, it does not displace hydrogen from water to form a metal hydroxide and hydrogen gas.
4)
a) 2Na + 2HCl -> 2NaCl + H2
b) 2Al + 6HCl -> 2AlCl3 + 3H2
c) Fe + 2HCl -> FeCl2 + H2
d) Zn + 2HCl -> ZnCl2 + H2
e) Cu + 2HCl -> No reaction
5)
a) 2Na + Cl2 -> 2NaCl
b) 2Al + 3Cl2 -> 2AlCl3
c) Fe + Cl2 -> FeCl3
d) Zn + Cl2 -> ZnCl2
e) Cu + Cl2 -> No reaction
6)
a)
Na + H2SO4 -> Na2SO4 + H2 (colourless solution)
Al + H2SO4 -> Al2(SO4)3 + H2 (colourless solution)
Fe + H2SO4 -> FeSO4 + H2 (green solution)
Cu + H2SO4 -> CuSO4 + H2 (blue solution)
Zn + H2SO4 -> ZnSO4 + H2 (colourless solution)
b)
All the metal sulfates formed are soluble.
1)Write equations showing how sodium oxide and zinc oxide are formed
2)i)Write equations to show how the following react with water;
a)Na
b)Al
c)Zn
d)Fe
e)Cu
ii)From the above equations,write down the reactivity series
3)Explain why copper remains unreactive with water
4)Using equations show how the following metals react with hydrochloric acid;
a)Na
b)All
c)Fe
d)Zn
e)Cu
5)Using equations show how the following metals react with chlorine gas(green yellow gas);
a)Na
b)All
c)Fe
d)Zn
e)Cu
6)Using equations show how the following metals (Na,Al,Fe,Cu,Zn)react with dilute sulphuric acid and;
a)Sate the colour of solution formed
b)State whether soluble or insoluble
1 answer