Question

1. Write an equation in slope-intercept form for the line that passes through (5,0) and is perpendicular to the line given by y = -5/2x + 6.

A: m = 2/5

y = mx + b

0 = (2/5)(5) + b

0 = 2 + b
b = -2

y = 2x/5 -2?

2. Write an equation in slope-intercept form for the line that passes through (0, 0) and is parallel to the line given by y = -6/7x + 1.

A: ?

Identify which lines are parallel.

3. y = -2x; y = 2x + 1; y = 2x; y = 2(x + 5)

A: All of the above.

4. -3y = x; y = -1/3x + 1; y = -3x; y + 2 = x + 4

A: y = -1/3x + 1; y = -3x?

5. y = -3x + 2; y = 1/2x - 1; -x + 2y = 17; 3x + y = 27

A: y = -3x + 2; 3x + y = 27?

Answer 1

Can someone please help me?

Answer 2

#1 ok
you can avoid solving for b by using the point-slope form:

y-0 = 2/5 (x-5)

#2 how could you get #1 and not get #2?
m = -6/7
point-slope form:
y-0 = -6/7 (x-0)
y = -6x/7
all this means is that b=0

#3 1st has slope -2
the others all have slope 2

#4 only the 1st two.
The slopes are -1/3, -1/3 -3,1

#5 almost. the slopes are
-3, 1/2, 1/2, -3
so, your answer is correct, but there are 2 pairs of parallel lines.

Answer 3

To clarify:

3. Incorrect; y = 2x + 1; y = 2x; y = 2(x + 5)

4. Incorrect; -3y = x; y = -1/3x + 1

5. I don't quite understand what you said.

Answer 4

I'm just saying that the two you picked are parallel, but so are the other two. Don't know how the question is structured, and how you can answer, but unless there's a typo, there are two possible choices.