1.which is most likely to be part of an ionic bond?
A. an atom with no valence electrons
B. an atom with one valence electron
C. an atom with two valence electrons
D. an atom with three valence electrons
My answer is C.an atom with two......
5 answers
Elements with 1, 2, or 3 valence electrons can form ionic bonds. I think the secret phrase here is "most likely" so I would go with B. All elements with one valence electron (except H and that CAN form a ionic bond as hydrides) form an ionic bond.
so the answer is B
okay for the next Question
3.) what is true about the element francium (Fr, atomic number 87)? choose all that apply.
A. it has seven valence electrons
B. it is likely to form ionic bonds
C. it is a nonmetal
D. it is in period seven
E. it is a metal
3.) what is true about the element francium (Fr, atomic number 87)? choose all that apply.
A. it has seven valence electrons
B. it is likely to form ionic bonds
C. it is a nonmetal
D. it is in period seven
E. it is a metal
If you can pick only one, yes, I would go with B.
For the next question, you should know all about this from the periodic table.
A. It is in group I; therefore it has 1 valence electron.
B. From the first question you know it is likely to form an ionic bond.
C. It is in the left most part of the periodic table which houses metals.
D. Look at the periodic table and count the period it is in.
E. See my response to C.
There are three correct answers listed.
For the next question, you should know all about this from the periodic table.
A. It is in group I; therefore it has 1 valence electron.
B. From the first question you know it is likely to form an ionic bond.
C. It is in the left most part of the periodic table which houses metals.
D. Look at the periodic table and count the period it is in.
E. See my response to C.
There are three correct answers listed.
For the original question, it is 1 valance electron.
1 answer