To find an equation that has the same solution for \( x \) as the equation \( x - 12 = 40 \), we first need to solve the given equation for \( x \):
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Start with the original equation: \[ x - 12 = 40 \]
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Add 12 to both sides: \[ x = 40 + 12 \] \[ x = 52 \]
Now, let's check each of the response options to see which one also gives \( x = 52 \):
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Option A: \( x + 12 = -40 \)
- Subtract 12 from both sides: \[ x = -40 - 12 = -52 \quad \text{(not 52)} \]
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Option B: \( 12 - x = 40 \)
- Rearranging gives: \[ -x = 40 - 12 \] \[ -x = 28 \quad \Rightarrow \quad x = -28 \quad \text{(not 52)} \]
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Option C: \( \frac{x}{2} = 14 \)
- Multiply both sides by 2: \[ x = 14 \times 2 = 28 \quad \text{(not 52)} \]
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Option D: \( \frac{x}{4} = 13 \)
- Multiply both sides by 4: \[ x = 13 \times 4 = 52 \quad \text{(is 52!)} \]
So, the equation that has the same solution as \( x - 12 = 40 \) is:
Option D: \( \frac{x}{4} = 13 \).