Y= x^2+12x=4 ????
I think maybe
y = x^2 + 12 x + 4 ????
x^2 + 12 x = y-4
x^2 + 12 x + (12/2)^2 = y - 4 + 36
(x+6)^2 = y+32
how about (-6,-32)
1.What is the vertex from the equation?
Y=x^2+12x=4
(Please show your work to show me the steps to get to the right answer.)
2. Use the quadratic formula to solve the equation.
x^2-7x-6=0
(Please show your work to show me the steps to get to the right answer. )
3.simplify the expression
(-2/)(8/)
(Please show your work to show me the steps to get to the right answer. )
3 answers
x^2-7x-6=0
a = 1
b = -7
c = -6
x = [ 7 +/- sqrt {49 -(4)(-7)(-6) } ] /2
= [ 7 +/- sqrt {49 -168 } ] /2
= [ 7 +/- sqrt {-119 } ] /2
are you sure that was not +6 = c ?
a = 1
b = -7
c = -6
x = [ 7 +/- sqrt {49 -(4)(-7)(-6) } ] /2
= [ 7 +/- sqrt {49 -168 } ] /2
= [ 7 +/- sqrt {-119 } ] /2
are you sure that was not +6 = c ?
-1/4 ????