#1 and #3 are the same type of problem.
Solve the two equations, once you have the x and y, just perform the required arithmetic.
I will do the first you do #3
add the equations:
4x = 12
x = 3
sub back into the 2nd (looks easier)
-3 + 3y = 9
3y = 12
y = 4
so x=3, and y = 4, then
x-y = 3-4
= -1
#2
I will assume you mean
-2x^-1 /(x^2y^-1)
= (-2/x)(1/x^2)(1/y)
= -2/(x^3 y)
1.What is the value of x-y if 5x-3y=3 and
-x+3y=9 ?
2.Rewrite -2x^-1 /x^2y^-1 with positive
exponents
3. What is the value of xy if x+5y=26 and
-x+y=4 ?
2 answers
Yes,but is that the answer to#2, because the multiple choice answers are:A.-2x^3y
B.2x^3/y C. -2y/x^3 D.-2y/x E.2y/x
Which one is it,please help me Reiny.
B.2x^3/y C. -2y/x^3 D.-2y/x E.2y/x
Which one is it,please help me Reiny.