Asked by sadia salem
1=what is the percntage yeild of carbon dioxide if 4 moles of octane are burnt to produce 1350g of carbon dioxide
2c8h18 + 25o2 = 16co2 + 18h2o
2c8h18 + 25o2 = 16co2 + 18h2o
Answers
Answered by
DrBob222
You really need to find the caps key and use it. o2 doesn't man anything to me. Example. CO is carbon monoxide; Co is cobalt; co is the abbreviation for company.
2C8H18 + 25O2 = 16CO2 + 18H2O
How much CO2 should be produced by 4 moles octane at 100%? That's 4 mols C8H18 x (16 mols CO2/2 mols C8H18) = 4*16/2 = 32 mols CO2.
How many grams is that? That's 32 mols CO2 x 44 g/mol = ? grams CO2. That is the theoretical yield (TY).
The actual yield (AY) is given in the problem as 1350 g.
% yield = (AY/TY)100 = ?
2C8H18 + 25O2 = 16CO2 + 18H2O
How much CO2 should be produced by 4 moles octane at 100%? That's 4 mols C8H18 x (16 mols CO2/2 mols C8H18) = 4*16/2 = 32 mols CO2.
How many grams is that? That's 32 mols CO2 x 44 g/mol = ? grams CO2. That is the theoretical yield (TY).
The actual yield (AY) is given in the problem as 1350 g.
% yield = (AY/TY)100 = ?
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