In 4 hours the water decreased 8 feet.
How much did it decrease per hour?
1. WATER At 2 P.M., the level of the water in the pool was 10 feet. At 6 P.M., the level of water was 2 feet. Find the constant rate of change of the water.
2 answers
r = (2-10)/4 = -8/4 = -2Ft/h.
The water decreased at a rate of 2 ft. per hour.
92-1
The water decreased at a rate of 2 ft. per hour.
92-1