I can't provide a test for you directly, but I can certainly help you review concepts related to one-variable equations and inequalities. Here are some key concepts and practice questions you might find useful for studying:
Concepts to Review:
-
One-Variable Equations:
- Standard form: Ax + B = C
- Solving for x: Isolate the variable by performing inverse operations (addition, subtraction, multiplication, division).
-
One-Variable Inequalities:
- Symbols: <, >, ≤, ≥
- Solving inequalities involves the same steps as equations, but remember to flip the inequality sign when multiplying or dividing by a negative number.
- Graphing inequalities on a number line.
-
Compound Inequalities:
- Solving and graphing statements that combine two inequalities (e.g., a < x < b).
-
Absolute Value Equations and Inequalities:
- Equations: |x| = a leads to two possible equations: x = a or x = -a.
- Inequalities: |x| < a and |x| > a; both have specific ways to express the solution set.
-
Word Problems:
- Translating real-world problems into equations or inequalities.
Practice Questions:
Equations:
- Solve for x: \( 2x + 3 = 11 \)
- Solve for x: \( 5(x - 2) = 3x + 4 \)
Inequalities:
- Solve for x: \( 3x - 5 > 4 \)
- Solve for x: \( -2(x + 3) ≤ 8 \)
Compound Inequalities:
- Solve for x: \( 1 < 3x + 2 < 10 \)
Absolute Value:
- Solve for x: \( |x - 4| = 7 \)
- Solve for x: \( |2x + 3| > 5 \)
Word Problem:
- A number decreased by 7 is at least 15. What is the number?
Sample Solutions:
-
Solution to 1: \[ 2x + 3 = 11 \implies 2x = 8 \implies x = 4 \]
-
Solution to 2: \[ 5(x - 2) = 3x + 4 \implies 5x - 10 = 3x + 4 \implies 2x = 14 \implies x = 7 \]
-
Solution to 3: \[ 3x - 5 > 4 \implies 3x > 9 \implies x > 3 \]
-
Solution to 4: \[ -2(x + 3) ≤ 8 \implies x + 3 ≥ -4 \implies x ≥ -7 \]
-
Solution to 5: \[ 1 < 3x + 2 < 10 \implies -1 < 3x < 8 \implies -\frac{1}{3} < x < \frac{8}{3} \]
-
Solution to 6: \[ |x - 4| = 7 \implies x - 4 = 7 \text{ or } x - 4 = -7 \implies x = 11 \text{ or } x = -3 \]
-
Solution to 7: \[ |2x + 3| > 5 \implies 2x + 3 > 5 \text{ or } 2x + 3 < -5 \implies x > 1 \text{ or } x < -4 \]
-
Solution to 8: Let the number be \( x \): \[ x - 7 ≥ 15 \implies x ≥ 22 \]
Feel free to work through these problems, and let me know if you have any questions or need further clarification on any topics!