Let's go through each question one by one.
Question 1:
Generate an equivalent expression for \( \sqrt[3]{216} \) in exponential form.
To express \( \sqrt[3]{216} \) in exponential form, we recognize it as \( 216^{1/3} \). Since \( 216 = 6^3 \), we can rewrite it as \( (6^3)^{1/3} = 6^{3 \cdot (1/3)} = 6^1 = 6 \). Therefore, the rational exponent is:
- \( \frac{1}{3} \)
However, for \( 216^{-1/3} \), which is what the equation states:
- The exponent is \( -\frac{1}{3} \).
Response:
- −1/3
Question 2:
Simplify \( 512125\sqrt{3} \).
To simplify the expression \( 512125\sqrt{3} \):
-
You need to express \( 512125 \) in exponential form. If we break it down:
- \( 512 = 2^9 \)
- So, \( \sqrt{3} = 3^{1/2} \)
Therefore, combining gives us: \[ 512 \cdot 125 \cdot 3^{1/2} = 2^9 \cdot 5^3 \cdot 3^{1/2} \]
In improper fractional simplification, this can lead to 5’s division.
Response:
- Since simplifications may vary, the closest logical answer is:
- 1
Question 3:
Equivalent expression to \( 81^{-1/2} \)
The expression \( 81^{-1/2} \):
- Can be rewritten using the negative exponent rule:
- \( 81^{-1/2} = \frac{1}{81^{1/2}} = \frac{1}{\sqrt{81}} = \frac{1}{9} \).
Response:
- 1/81^{1/2}.
Question 4:
True or false: \( 10^{-1/3} = -10\sqrt[3]{3} \)
First, \( 10^{-1/3} \) is \( \frac{1}{10^{1/3}} \) or \( \frac{1}{\sqrt[3]{10}} \). The right-hand side \( -10\sqrt[3]{3} \) has a negative sign and does not match these forms exactly, therefore:
Response:
- False, because according to the Negative Exponent Rule, the equation should be \( 10^{-1/3} = -\frac{1}{\sqrt[3]{10}} \).
Question 5:
Is the equation \( 3^{-5} \cdot (81^{\frac{1}{4}})^{3} \cdot 3^{-4} = 3^{-6} \) true or false?
To simplify \( 3^{-5} \cdot (81^{1/4})^{3} \cdot 3^{-4} \):
- \( (81^{1/4})^{3} = 81^{3/4} = (3^4)^{3/4} = 3^{3} \).
- Now combine:
- \( 3^{-5} \cdot 3^{3} \cdot 3^{-4} = 3^{-5 + 3 - 4} = 3^{-6} \).
Thus, we find:
- \( 3^{-5} \cdot (81^{1/4})^{3} \cdot 3^{-4} = 3^{-6} \).
Response:
- True. The numerator simplifies to \( 3^{-2} \) and \( 3^{-2} \cdot 3^{-4} = 3^{-6} \).
Feel free to ask for clarifications or more details for any item!