Let's go through each question one by one:
Question 1:
- Using the properties of exponents to generate an equivalent expression, which of the following would be the rational exponent of the equivalent expression to \(216^{-\frac{1}{3}}\) if it were written in exponential form instead of radical form?
- The expression \(216^{-\frac{1}{3}}\) means the same as \(-\sqrt[3]{216}\), but in exponential form, it is already given as \(216^{-\frac{1}{3}}\). Thus the rational exponent is indeed \(-\frac{1}{3}\).
Answer: \(-\frac{1}{3}\)
Question 2:
- Which of the following is an equivalent expression for \(512^{\frac{1}{25}}\) when simplified using exponent properties?
- We can express \(512\) as \(2^9\) (because \(2^9 = 512\)). Then, we have \((2^9)^{\frac{1}{25}} = 2^{\frac{9}{25}}\). This does not match the response options directly, but looking at the options again will clarify that we have \((2^{\frac{9}{25}}) \neq 1, 5^0, 15, 5\sqrt{5}\). Since all options do not seem to apply directly, you would need to select the option that best aligns with the available responses—none directly fit, but \(5^0 = 1\) is just always true in exponent terms.
Answer: 1
Question 3:
- Which of the following is an equivalent expression to \(81^{- \frac{1}{2}}\)?
- The expression \(81^{- \frac{1}{2}}\) can be rewritten as \(\frac{1}{\sqrt{81}} = \frac{1}{9}\).
Answer: \(\frac{1}{\sqrt{81}}\)
Question 4:
- Use the properties of exponents to determine whether the equation \(10^{- \frac{1}{3}} = -10^{\frac{1}{3}}\) is true or false.
- The left side, \(10^{- \frac{1}{3}}\), is the same as \(\frac{1}{10^{\frac{1}{3}}}\), while the right side is the negative of the cube root of \(10\). They are not equivalent.
Answer: False, because according to the Negative Exponent Rule, the equation should be \(10^{- \frac{1}{3}} = \frac{1}{10^{\frac{1}{3}}}\)
Question 5:
- Is the equation \(3^{-5} \cdot (81^{\frac{1}{4}})^{3} \cdot 3^{-4} = 3^{-6}\) true or false?
- Let's simplify the left side:
- \((81^{\frac{1}{4}})^{3} = 81^{\frac{3}{4}} = (3^4)^{\frac{3}{4}} = 3^3\)
- Therefore the left side becomes \(3^{-5} \cdot 3^3 \cdot 3^{-4}\)
- By adding the exponents: \(-5 + 3 - 4 = -6\)
- Thus the left side simplifies to \(3^{-6}\), which equals the right side.
Answer: True. \((81^{\frac{1}{4}})^3 = 3^2\) and \(3^{-5} \times 3^3 \times 3^{-4} = 3^{-6}\)
Let me know if you need any further assistance!