1)
KaKb = Kw = 1E-14
2)
I have no idea what NaC2 is.I suspect you were trying to write NaC2H3O2. I would expect the pH of a 0.1M solution of NaC2H3O2 to be the same as a 0.1M solution of KC2H3O2.
The pH is determined by the hydrolysis of the C2H3O2^- ion and that would be the same for both solutions; i.e., Kb for C2H3O2^- is the same for both.
1) using kb for NH3 calculate ka for NH4+ ion. Compare this value with that calculated from your measured ph's?
2) how should the pH of a 0.1M solution of NaC2 at H3O2 compare with that of a 0.1 M solution of KC2H3O2? Explain briefly?
THANK YOU!
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