Asked by maczindahouse
1. Use the table of systolic blood pressures (in mm Hg) in each arm to determine a line of regression that predicts the pressure in the left arm given the pressure in the right arm.
Right Arm: 102; 101; 94; 79; 79
Left Arm: 175; 169; 162; 146; 144
a. y = 1.20 + 50.1x
b. y = 0.981 + 0.991x
c. y = 0.991 + 0.981x
d. y = 50.1 + 1.20x
I am very confused. Can someone please help?
Right Arm: 102; 101; 94; 79; 79
Left Arm: 175; 169; 162; 146; 144
a. y = 1.20 + 50.1x
b. y = 0.981 + 0.991x
c. y = 0.991 + 0.981x
d. y = 50.1 + 1.20x
I am very confused. Can someone please help?
Answers
Answered by
Silhouette
1.B This is not a good model because the residual plot has an obvious pattern.
2.D y=-157+40 2x yes, because the r-value is high.
3.D y=0.808+0.863 17.2/mil gal
4.D This is a good model because the residual plot does not show an obvious pattern nor does it become thicker toward one of the ends.
5.B 1206
6.B 50.1+1.20(x)
7.D y=-0.124_0.00945x
8.B 64
9.A y=2.55x-6.435
10.A 1236 spots
2.D y=-157+40 2x yes, because the r-value is high.
3.D y=0.808+0.863 17.2/mil gal
4.D This is a good model because the residual plot does not show an obvious pattern nor does it become thicker toward one of the ends.
5.B 1206
6.B 50.1+1.20(x)
7.D y=-0.124_0.00945x
8.B 64
9.A y=2.55x-6.435
10.A 1236 spots
Answered by
Josselin
Did you find the answer
Answered by
Kai
@josselin
Answer is…
D. Y=50.1+1.20x
Answer is…
D. Y=50.1+1.20x
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