1. Two children balance a see-saw in horizontal equilibrium. One weighs 80 lb. and the other weighs 60 lb. and is sitting 4ft. from the fulcrum. Find the force the fulcrum applies to the beam and the distance to the fulcrum to the 80 lb. child. (Neglect the mass of the see-saw)

Answer 1

If I recall my highschool physics,
W1 * D1 = W2 * D2
80D1 = 60(4)
D1 = 240/80 = 3

Answer 2

to find the force...you just subtract the two weights?