1. Tin and oxygen gas are reacted together to form Tin (IV) oxide, a solid. If a piece of tin foil, 8.25cm x 21.5cm x 0.60mm (density = 7.28g/cm3) is exposed to oxygen and all the tin reacts, what is the mass of the oxidized tin foil? (98.4g)

Question

1. Tin and oxygen gas are reacted together to form Tin (IV) oxide, a solid.  If a piece of tin foil, 8.25cm x 21.5cm x 0.60mm (density = 7.28g/cm3) is exposed to oxygen and all the tin reacts, what is the mass of the oxidized tin foil? (98.4g)
   2. From the information in problem 1, if air is about 21% oxygen by volume (d=1.309g/L) at 25C, atm).  How many liters of air are required to completely react ith the tin foil? (76L)
   3. Oxygen masks for producing O2 in emergency situations contain potassium superoxide, KO2.  It reacts with CO2 and H2O in exhaled air to produce oxygen and potassium hydrogen carbonate.  If a person wearing such a mask exhales 0.70g carbon dioxide perminute, how many grams of KO2 are consumed in 25 minutes? (28g)

PC · Answer

Can you start with finding the weight of the tin foil?

Tin (IV) means that the resulting compound is Sn++++, or equivalent meaning:
Sn + 2O2 = SnO4

With the ATOMIC mass of tin=118.17, and 16 for O2, you should be able to complete the calculations.

DrBob222 · Answer

Sn(IV) oxide is SnO2. The correct equation is Sn + O2 ==> SnO2.

PC · Answer

Oops, thanks Dr. Bob.

Anonymous · Answer

Can someone explain how to do this?