(4/3)π r^3 = 4846.59
r^3 = ...
r = cuberoot(....) =
I have a different answer from yours.
1. The volume of a mini-basketball is approximately 4846.59 cubic centimeters. What is the approximate radius of a mini-basketball?
A. 10.5 centimeters
B. 11.5 centimeters
C. 21 centimeters**
D. 23 centimeters
Need help, please!
Thanks
9 answers
v = 4/3 π r^3
r = cuberoot [(4846.59 * 3/4) / π]
r = cuberoot [(4846.59 * 3/4) / π]
Where did you get 4/3?? I'm confused
We both assumed you knew the formula for the volume of a sphere
= (4/3)π r^3
= (4/3)π r^3
Oh, ok
I remember now
I remember now
4846.59 cubic centimeters
So, r = cubic root [(4846.59 * 3/4) / π]
r ≈ 9.57 cm
Therefore, the approximate radius of a mini-basketball is 9.57 centimeters.
r ≈ 9.57 cm
Therefore, the approximate radius of a mini-basketball is 9.57 centimeters.
4846.59 cubic centimeters
Sorry for the confusion. Here's how we can solve it.
The formula for the volume of a sphere is given by:
V = (4/3)πr^3
We know that the volume of the mini-basketball is approximately 4846.59 cubic centimeters. So we can write:
4846.59 = (4/3)πr^3
Multiplying both sides by 3/4π, we get:
4846.59 * (3/4)π = r^3
Taking the cube root of both sides, we get:
r = (4846.59 * (3/4)π)^(1/3) ≈ 9.57
Therefore, the approximate radius of the mini-basketball is 9.57 centimeters.
The formula for the volume of a sphere is given by:
V = (4/3)πr^3
We know that the volume of the mini-basketball is approximately 4846.59 cubic centimeters. So we can write:
4846.59 = (4/3)πr^3
Multiplying both sides by 3/4π, we get:
4846.59 * (3/4)π = r^3
Taking the cube root of both sides, we get:
r = (4846.59 * (3/4)π)^(1/3) ≈ 9.57
Therefore, the approximate radius of the mini-basketball is 9.57 centimeters.
1 answer