(j-5) + (r-5) = 44
(j+22) + 52 = 2 (r+22)
j + r = 54
so
j = (54-r)
then
(54 - r + 22) + 52 = 2 r + 44
128-r = 2 r + 44
3 r = 84
r = 28
j = 26
=================================
x and (41-x)
(41-x) - x = 5
etc
=========================
2 L + 2 W = 320
W = (L-40)
so
L + (L-40) = 160
etc
1. The sum of the ages of James and Remy 5 years ago was 44. Twenty-two years from now, James' age will be 52 less than twice3 Remy's age then. Find their present ages.
2. Two numbers have a sum of 41. Their difference is 5. What are the numbers?
3. The perimeter of a football field is 320 yards. Its length measures 40 yd more than its width. Find the dimensions of the field.
2 answers
(j-5) + (r-5) = 44
(j+22) + 52 = 2 (r+22)
j + r = 54
so
j = (54-r)
then
(54 - r + 22) + 52 = 2 r + 44
128-r = 2 r + 44
3 r = 84
r = 28
j = 26
=================================
x and (41-x)
(41-x) - x = 5
etc
=========================
2 L + 2 W = 320
W = (L-40)
so
L + (L-40) = 160
etc
(j+22) + 52 = 2 (r+22)
j + r = 54
so
j = (54-r)
then
(54 - r + 22) + 52 = 2 r + 44
128-r = 2 r + 44
3 r = 84
r = 28
j = 26
=================================
x and (41-x)
(41-x) - x = 5
etc
=========================
2 L + 2 W = 320
W = (L-40)
so
L + (L-40) = 160
etc